Pick given properties from a JSON representation

By default, JSON.stringify(value) will pull all serializable properties of value.
const resources = [
{
name: '1 LOC',
description: 'Favorite JavaScript utilities in single line of code',
link: 'https://1loc.dev',
},
{
name: 'CSS Layout',
description: 'A collection of popular layouts and patterns made with CSS',
link: 'https://csslayout.io',
},
{
name: 'HTML DOM',
description: 'How to manage HTML DOM with vanilla JavaScript',
link: 'https://htmldom.dev',
},
{
name: 'Responsive Design Patterns',
description: 'A collection of patterns to create a responsive web page',
link: 'https://responsive.page',
},
{
name: 'Front-end Tips',
description: 'Super tiny, quick tips, tricks and best practices of front-end development',
link: 'https://getfrontend.tips',
},
{
name: 'this VS that',
description: 'The differences between ___ and ___ in the front-end development',
link: 'https://thisthat.dev',
},
];
JSON.stringify(resources);
/*
[
{
"name": "1 LOC",
"description": "...",
"link": "..."
},
{
"name": "CSS Layout",
"description": "...",
"link": "..."
},
{
"name": "HTML DOM",
"description": "...",
"link": "..."
},
...
]
*/
If you want to receive some particular properties, then pass them to the second parameter:
// Only pick the `name` property
JSON.stringify(resources, ['name']);
// Pick the `name` and `link` properties
JSON.stringify(resources, ['name', 'link']);
You can use the same tip when logging an array to the Console.

See also