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#87

Create a function that accepts a single parameter

Topics: JavaScript

Quite often, we use the map function to transform each item of an array into a new one. However, it's common to see an issue if we don't pass the parameter to the mapper function.

For example, the following code converts each item of array into a number:

['1', '2', '3', '4', '5'].map(v => parseInt(v));

// [1, 2, 3, 4, 5]

However, the result isn't correct if we shorten it as below:

['1', '2', '3', '4', '5'].map(parseInt);

// [1, NaN, NaN, NaN, NaN]

The issue is caused by the fact that the mapper function accepts three parameters which are the array item, index, and the array.
Calling .map(parseInt) means that we pass the item index to parseInt as the second parameter. As a result, we will see NaN.

This leads to a requirement of building a function that accepts only the first parameter, and ignore the remaining parameters.

const unary = fn => params => fn(params);

The unary function creates a wrapper of a function, and ignores all parameters except the first one. With that function in our hand, we can pass the mapper to the map function like this:

['1', '2', '3', '4', '5'].map(unary(parseInt));

// [1, 2, 3, 4, 5]

More

Fix a typo or suggest an improvement
#88 Save a few bytes when checking the existence of module